Solve This!
Pens
II In order to find the optimum pen, or the pen with the greatest area, I knew
that I needed to organize all the possible rectangles using 48 meters. I started
with the obvious one, 1 by 23, and drew it on quarter inch graph paper. Then
I worked up by decreasing the length by one and increasing the width by one
each time. I continued this way until I was sure that I had all of the possible
rectangles. I knew this because I had used all of the numbers up to 23. I couldnt
use 24 because there would be no width.
The optimum pen was exactly a square. On Pens One the optimum pen was also a
square. I think that the reason for this is that in a square there are more
square centimeters that dont use any fencing.
| Length | Width | Area | Perimeter |
| 23 | 1 | 23 | 48 |
| 22 | 2 | 44 | 48 |
| 21 | 3 | 63 | 48 |
| 20 | 4 | 80 | 48 |
| 19 | 5 | 95 | 48 |
| 18 | 6 | 108 | 48 |
| 17 | 7 | 119 | 48 |
| 16 | 8 | 128 | 48 |
| 15 | 9 | 135 | 48 |
| 14 | 10 | 140 | 48 |
| 13 | 11 | 143 | 48 |
| 12 | 12 | 144 | 48 |
Click here to go back to Pens II.