Overloading Derived Classes

Overloading a derived class is the same as overloading any kind of class. Here is a skeleton example of Overloading a derived class.

//superset(derived class) class Employee: public Business { public: Employee(); //constructor Employee(int age); //overloaded Employee(int age, long int Sal); //overloaded Employee(int age, long int Sal, int years); //overloaded ~Employee(){}; void setAge(int age) {itsAge = age;} int getAge() const {return itsAge;} void Comment() const {cout <<"I sure do love programming!n";} void WakeUp() const {cout <<"Wow! I sure didn't get enough sleep!n";} void Sleep() const {cout <<"Goodnight!n";} protected: int itsAge; };

In this example, the derived class is named Employee and the base class is named Business. As you can see, overloading the constructor of a superset is the exact same as overloading the constructor of a regular class. You can also override the methods of the base class. For instance, if you had a base class named Human, and two derived classes named Male and Female. If you wrote:

//tq.h //overriding //base class class Human { public: Human() { itsAge = 16;} ~Human(){}; int getAge() const { return itsAge;} void setAge(int x) { itsAge = x;} void Speak() const {cout << "I'm a human, hello world!n";} protected: int itsAge; }; //derived class class Male: public Human { public: Male(){}; ~Male(){}; void Speak() const { cout <<"I'm a male, hello world!n";} }; //derived class class Female: public Human { public: Female(){}; ~Female(){}; void Speak() const { cout <<"I'm a female, hello world!n";} };

Here is the main .cpp:

#include <iostream.h> #include "tq.h" int main() { Human Human1; Human1.Speak(); Male Male1; Male1.Speak(); Female Female1; Female1.Speak(); return 0; }

If you compiled this program, you would notice that each object returns their own message, even though each Class has the same name and return type. Please Rate this Code:

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