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Contents
Ratio for Complementary Angles
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Complementary Angles In the triangle PQR in the diagram, ÐP and ÐR are complementary angles as ÐP + ÐR = 90°
Example
a) sin
(90° - q) = cos q
b) cos
(90° - q) = sin q
c) tan
(90° - q) = 
cos
(90° - q) = b/c sin q
= b/c
tan (90° - q) = a/b
 Thus, sin
(90° - q) = cos q
cos
(90° - q) = sin q
tan
(90° - q) =
Example 2
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Using the right-angles triangle in the diagram, show that
sin (90° - q) = a/c cos q
= a/c
