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Contents
Tangents from External Point
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Tangents from External Point
Example
1
i) AP = BP ii)
ÐAPO = ÐBPO
iii) ÐAOP
= ÐBOP
△AOP
and △BOP are congruent (RHS
Property)
AP =
BP
ÐAPO
= ÐBPO and ÐAOP
= ÐBOP
We can
conclude that:
a)
tangents drawn to a circle from an external point are equal
b) the
tangents subtend equal angles at the centre
c) the
line joining the external point to the centre of the circle bisects the angle
between the tangents.
Example
2
![]() (a) the
value of
x
b) ÐAOB
(c) the
are bounded by AB, BC and the arc AC.
OB = (x + 5)cm
(x + 5)2 = x2 + 82
x2 + 10x + 25 = x2 + 64
10x = 64 - 25 = 39
x = 3.9
(b) tan ÐAOB
= 8/3.9
ÐAOB = 64.0° (1 d.p.)
(c) Area
AOB = ½(8)(3.9) cm2 = 15.6cm2
Area minor sector AOC = 64.01/360 x p(3.9)2 cm2 = 8.496
= 8.50 cm (3.s.f.)
Area bounded = (15.6 - 8.496)cm2
= 7.10cm2 (3 s.f.)
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