Simultaneous Equations
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The solutions
are x= -½ & y =3.
Let y be the second speed
2x + 3y = 252km --------(1)
4x + y = 244km --------(2)
From (1): 2x = 252 - 3y --------(3)
substitute (3) into (2): 2(252 - 3y) + y = 244
504 - 6y + y = 244
260 = 5y
y = 52
substitute y = 52 into (1): 2x = 252 - 156
x = 48
The two speeds are 48km/h and 52km/h
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