Partial Fractions

 

 

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Partial Fractions

 

Linear Factors

 

Repeated Linear Factors

 

Quadratic Factors

 

Improper Fractions

 

Quiz

 

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Partial Fractions Quiz

Now that you've gone through our explanation on the idea of partial fractions, take this short quiz to find our how much you have learnt.
 
Express the following in partial fractions:
 
             
Answer
 
 
             
Answer
 
 
Answer
 
 
  Let
        
 
    By cover-up rule,
 
                  D = 1 / (1 + 1)
                     = 0.5
 
    (x - 1)2(Ax + B) + C (1 + x2) (x - 1) + 0.5 (x2 + 1) = 1
    x3 (A + C) + x2 (0.5 - C - 2A + B) + x (A + C - 2B) + B - C + 0.5 = 1
 
    Comparing coefficient of x3 term:
                                  A + C = 0
                                        A = -C
 
    Comparing coefficient of constant term:
                         B - C + 0.5 = 1
                                        B = C + 0.5
 
    Comparing coefficient of x term:
                           A + C - 2B = 0
             -C + C - 2 (C + 0.5) = 0            substituting above equations
                                        C = -0.5
 
                              A = 0.5,    B = 0
 
Hence,
       
 
 
  Let
         
    
      From above identity, A = 2
 
      Using cover-up rule,
                      C = (2+2-3+8) / (1+2)
                         = 3
                    
 
     2x3 + 2x2 - 3x + 8 = (2x + B)(x - 1)(x + 2) + 3(x + 2) - 2(x - 1)
 
     Let x = 0,
        -2B + 6 + 2 = 8
                       B = 0
 
Hence,
        
 
 
  Let
         
 
    From identity,  A = 1
 
    Using "cover-up" rule,
              
 
   2x4 + 5x3 +12x2 + 20x - 1 = (x + B)(x2 + 4)(2x - 1) + (Cx + D)(2x -1) + 3(x2 + 4)
                                        = 2x4 + x3(2B - 1) + x2(2C - B + 11) + x(8B - C + 2D -4)
                                            + 12 - 4B - D
 
   Compare coefficient of x3:
                               2B - 1 = 5
                                     B = 3
 
   Compare constant term:
                        12 - 4B - D = -1
                                     D = 1          substituting B = 3
 
   Compare coefficient of x2:
                       2C - B + 11 = 12
                                     C = 2          substituting B = 3
 
Hence,