Inequalities
![]()

1<|ax
+1| and |ax +1|
2
ax
+ 1 > 1 or ax + 1 < -1 and -2
ax + 1
2
ax
> 0 ax <-2 and -3
ax
1
x
< 0 or x >
and ![]()
x![]()
![]()
Sketch a number line
Solution
is ![]()
x
0
or
<x![]()
Thus, -3 < x < 0 or x > 4
![]()