Initial Value Problems

A basic and simple way to solve for that C when doing Anti derivatives.

Given Information:

(dy/dx)=3x²

when x = 1, y = -1

 

The Anti derivative of the equation above is:

y = x³ + C

 

Now simply plug in 1 for x and -1 for y and solve.

-1= 1 + C  »  -2 = C

 

So the equation is:

y = x³ -2

 

 

[Back to Anti - Derivatives] [Calculus Home Page] [Graph Calc]