1. A bomb is dropped from a hovering helicopter. It takes 4 seconds to hit.
How high is the helicopter?
2. How fast must a bullet be shot to reach a height of 250m?
78.4m
Here, we need to use one of our substitution equations.

d = 0m/s * 4s + 0.5 * -9.8m/s2 * (4s)^2

d = -78.4m, and since height is a scalar, we can drop the negative leaving 78.4m
70m/s
Again, we need to use one of our substitution equations.

2 * -9.8m/s2 * 250m = (0m/s)^2 - vo^2

-4900m2/s2 = -vo^2

70m/s

