1. An object dropped near the earth's surface falls 4.9m in the first second.
If the moon's gravitational pull is about 1/6 that of the earth's, how long
would it take the same object to fall the 4.9m?
2. A 5kg block is pulled westward across a frictionless horizontal surface by
a 30N force applied at 87° angle above the horizontal?
6 seconds
This problem is actually much simpler than it sounds. Since the gravitational force of the
moon is 1/6 that of the earth, an object would fall 1/6 as fast. All you need to do is multiply
the original time by 6.

1s * 6 = 6s
a. What is the block's acceleration?
b. What is the normal force?
a. 0.314m/s^2
b. 19.04N
First, we find the components of the force, and then we use Newton's second law.

30N cos 87° = 1.57N

30N sin 87° = 29.96N

1.57N = 5kg * a

a = 0.314m/s^2
For part b, we will simply subtract the y component of the force from gravity to find the
normal force.

FG = 9.8m/s^2 * 5kg

FG = 49N

49N = FN + 29.96N

FN = 19.04N

