Washer Example Problem

Situation: You must find the volume of the solid formed by revolving the region bounded by the graphs of y = SQRT(x) and y = x2 about the x-axis, as shown below.

Wash 1 Wash 2

Solution: As seen in the images above, you should notice that the outer and inner radii are as follows.

Outer Radius
R(x) = SQRT(x)

Inner Radius
r(x) = x2

Integrating between 0 and 1 produces
             b
V = pi §  ([R(x)]2 - [r(x)]2) dx
             a

          1
= pi §  (x - x4) dx
          0
                           1
= pi [x2/2 - x5/5]
                           0

= (3pi)/10.