Answers for Section 3 - Segments
1) LE = MR and EG = RA - Given
AR+RM=AM and LE+EG=LG - Segment addition
RM+AR=LG and EG+LE=AM - Substitution
LG = MA - Substitution
2) AB=BC and BC=CD - Given
AB = CD Transitive
3) QR=RS - Given
QS = QR + RS - Segment Addition
QS = RS + RS - Substitution
QS = 2RS - Addition
4) AC = AD and AB = AE - Given
AB+BC = AC and AE+ED = AD - Segment addition
AE+ED = AC - Transitive
AB+ED = AC - Substitution
BC = AC-AB and ED = AC-AB - Subtraction
BC = ED - Transitive
5) Segment ABCD - Given
AB + BC = AC - Segment Addition
AC + CD = AD - Segment Addition
AB + BC + CD = AD - Substituion
Divide the number you got correct by five, and then you will get your grade percentage.