Examples:
1. Find the perimeter of the figure given below.

AB = FE+ DC
= 8+8
= 16cm
CB = DE + FA
= 6 + 6
= 12cm
Perimeter of the figure =6+8+6+8+12+16
= 56 cm
2. ABCD is a rectangle. What is the area of the shaded part?

Area of rectangle = 20 x 15
= 300 cm2
Area of unshaded triangle = 20 x 15
2
= 150 cm2
Area of shaded part = 300 - 150
= 150 cm2
3. Find the area of the shaded part. (Take pi to be 22/7)

Radius of circle = 14/2
= 7 cm
Area of semicircle = ½ x 22/7 x 7 x 7
= 77 cm2
3. Find the perimeter of the quadrant. (Take P to be 3. 14)
Diameter of circle = 7 x 2
= 14 cm
Circumference of quadrant = 1/4 x 3.14 x 14
= 10.99 cm
Perimeter of quadrant = 10.99 +7 + 7
= 24.99 cm