Solution
Notice that in the beginning, the points form an
equilateral triangle. By symmetry, they will always form an
equilateral triangle. Suppose that at time t the points
are in an equilateral triangle with sides a(t). At the
time
point A will have moved v
toward
point B, point B will have moved v
toward
point C, and point C will have moved v
toward
point A. Call these new points A', B', and C'.

As you can see in the diagram the new side a(
) can be found
by the Law of Cosines.

Then, if we subtract a^2(t) from both sides, factor the left-hand
side, and divide both sides by
we
have

Now if
,
the first factor on the left-hand side becomes a(t)' by
definition of a derivative, the second factor becomes
2a(t) and on the right-hand side, the last addend becomes
zero.
![]()
a(t) cancels out on both sides, so we integrate to
obtain
![]()
We know that when t=0, the side a(t) is 1,
therefore the constant C = 1. Also it is given that
v = 50. We have to find the time t when
a = 0.
