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The problems you missed are listed below with answers and explanations.  Look over the explanation for each problem so you can understand why you missed it!

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'); resetdisplay(); for(var i = 0; i <10; i++) { ganswer[i] = prompt(question[i],""); if (ganswer[i] == "quit" || ganswer[i] == "QUIT" || ganswer[i] == "Quit") { break; } q++; if (ganswer[i] == answer[i]) { c++; } else { rightans[i] = 0; w++; } resetdisplay(); } for(var i = 0; i < 10; i++) { if (rightans[i] == 0) { expl = expl + explain[i]; } } parent.frames[0].document.write(expl); parent.frames[0].document.write("
"); } question[0] = 'Are similiar polygons congruent?'; question[1] = 'Are there any rules for finding similiar triangles that are similiar to the rules of finding congruent triangles?'; question[2] = 'Are congruent triangles similiar?'; question[3] = 'Are the angle measures of similiar trianlges different?'; question[4] = 'Can Side-angle-side be used to prove similarity between triangles?'; question[5] = 'Side A on a triangle has a length of 8, side B is 4, a similiar triangle has side A length of 4, what is the length of side B?'; question[6] = 'Angle A is 45 degrees, a similiar triangle has angle B measuring as 70 degrees, what is angle A on the second triangle?'; question[7] = "Two similiar triangles have an angle measuring at 70 degrees, the opposite sides are 4 and 6, one of the other sides on the smaller measures as 2 what is the length of the larger's side?"; question[8] = 'Given that two isosceles triangles are congruent, one has a side length of 2 and an angle measure of 60, what is the length of the base of the other triangle?'; question[9] = 'Can similiar triangles have side lengths of 2, 3, 4, and 4, 6, 8?'; answer[0] = 'no'; answer[1] = 'yes'; answer[2] = 'yes'; answer[3] = 'no'; answer[4] = 'yes'; answer[5] = '2'; answer[6] = '45'; answer[7] = '3'; answer[8] = '2'; answer[9] = 'yes'; explain[0] = '#1

Similiar polygons are polygons that are proportional. Congruent polygons are equal. Therefore a similiar polygon is not congruent.

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To find similiar polygons you can use rules very similiar to those for finding congruency. The sides are not equal, but proportional.

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Congruent triangles are similiar. They are equal and also proportional. The proportion is 1 to 1.

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The angle measures of similiar triangles must be the same. Only sides can be proportional. (If the angles change, they won't add up to 180 degrees.)

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Side-angle-side can be used to prove similiarity, but when using the formula you must realize that the side will not be equal. The ratio of one side over the same on the other triangle will be the same.

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Since similiar triangles are proportional, we must first find the proportion. We know both side A's lengths, so we take the length of the first triangle's side A and divide it by the second triangle's side A. Which gives us 2. Then we can take the length of side B on the first triangle and divide it by our proportion, so we have 4 divided by 2. Which gives us the length of 2 for our answer.

"; explain[6] = '#7

Since the triangles are similiar, the angles must be the same. Angle A is 45 on the first triangle, so it must be 45 on the second also.

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First we need to find the ratio. 4/6 gives us 2/3 then we divide 2 by 2/3 which gives us 2*3/2 which gives us 6/2 which simplifies to 3 as our answer.

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Since we know the triangle is isosceles, we then know that 2 of the angles are the same. If one of the angles is 60, we know that all 3 angles must be 60 because there is no possible way to have a 60 degree angle in an isosceles triangle without it also being equilateral. (If it is a base angle, then the other base angle is 60 which leaves 60 for the vertex angle, if it is the vertex angle then it leaves 120 for the base angles which would make them 60.) So if it is now an equilateral triangle, we know that all the sides are equal. So the length is 2.

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First we must check to make sure they are valid side lengths for a triangle, so we add together 2 sides and make sure that the sum is greater than the 3rd side for every combination. And both sets of lengths pass. Then we check to see if they are proportional. And they are. So yes.

'; rightans[0] = 1; rightans[1] = 1; rightans[2] = 1; rightans[3] = 1; rightans[4] = 1; rightans[5] = 1; rightans[6] = 1; rightans[7] = 1; rightans[8] = 1; rightans[9] = 1; //-->