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Answers and Explanations'); parent.frames[0].document.write('

The problems you missed are listed below with answers and explanations.  Look over the explanation for each problem so you can understand why you missed it!


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'); resetdisplay(); for(var i = 0; i <10; i++) { ganswer[i] = prompt(question[i],""); if (ganswer[i] == "quit" || ganswer[i] == "QUIT" || ganswer[i] == "Quit") { break; } q++; if (ganswer[i] == answer[i]) { c++; } else { rightans[i] = 0; w++; } resetdisplay(); } for(var i = 0; i < 10; i++) { if (rightans[i] == 0) { expl = expl + explain[i]; } } parent.frames[0].document.write(expl); parent.frames[0].document.write("
"); } question[0] = 'What is the midpoint of a line with endpoints of (-3,4) and (10, -5)'; question[1] = 'Given a line with slope 2 and passing through the point (0,0), what is the slope-intercept equation?'; question[2] = 'How far apart are the points (1,1) and (-10, 9)?'; question[3] = 'How far is it from the end point to the midpoint of the line that has end points of (3,3) and (10,10)'; question[4] = "What's the slope of the line with equation y=8x+1?"; question[5] = 'Find the midpoint of (1,1) and (4,4)'; question[6] = 'What is the length of (1,1) and (4,4)'; question[7] = 'Using a coordinate plane to help you, a circle is drawn with a center point of (4,0) and an egde point of (0,0). What is the radius?'; question[8] = 'What is the distance between (0,0) and the midpoint of the line with endpoints of (5,5) and (9,2)?'; question[9] = "A circle is drawn with its center point on the midpoint of the line (1,2)-(8,5). The circle's outer edge reaches (0,0). What is the diameter?"; answer[0] = '(3.5,-.5)'; answer[1] = 'y=2x'; answer[2] = 'SQRT(185)'; answer[3] = 'SQRT(24.5)'; answer[4] = '8'; answer[5] = '(2.5,2.5)'; answer[6] = '3SQRT(2)'; answer[7] = '4'; answer[8] = 'SQRT(61.25)'; answer[9] = 'SQRT(130)'; explain[0] = '#1

Using the midpoint formula we arrive at the answer of (3.5,-.5)


'; explain[1] = '#2

Using slope-intercept form, we start of with y=mx+b. m=slope, so y=2x+b, and b=intercept which is 0. So the answer is y=2x.


'; explain[2] = '#3

Using the distance formula (remember this is derived from the pythagorean theorem) we can get the answer of SQRT(185)


'; explain[3] = '#4

Using the midpoint formula we get a midpoint of (7.5,7.5). Using the distance formula (remember this is derived from the pythagorean theorem) we can get the answer of SQRT(24.5). It is not proper to have a decimal in a square root, but since we usually use calculators to do work of this difficulty, we have left the decimal in for simplicity.


'; explain[4] = '#5

Since this equation is in slope intercept form we can simply take the number that is in the slope spot which is 8.


'; explain[5] = '#6

Using the midpoint formula we arrive at the answer of (2.5,2.5)


'; explain[6] = '#7

Using the distance formula (remember this is derived from the pythagorean theorem) we can get the answer of 3SQRT(2)


'; explain[7] = '#8

Since the center is at (4,0) and the edge is along (0,0) you can use the distance formula and get an answer of 4.


'; explain[8] = '#9

First you must find the midpoint of the line, which is (7,3.5). Then you can use the distance formula and get an answer of SQRT(61.25). It is not proper to have a decimal in a square root, but since we usually use calculators to do work of this difficulty, we have left the decimal in for simplicity.


'; explain[9] = '#10

First you must find the midpoint, which is (4.5, 3.5). Then use the distance formula. This will give you the radius of SQRT(32.5). Then multiply by 2 to get the diameter. Since this answer has a fraction within the SQRT() you should multiply the 2 through, but you must square it first. So the answer is SQRT(130).


'; rightans[0] = 1; rightans[1] = 1; rightans[2] = 1; rightans[3] = 1; rightans[4] = 1; rightans[5] = 1; rightans[6] = 1; rightans[7] = 1; rightans[8] = 1; rightans[9] = 1; //-->