Posted by Subhotosh Khan on December 04, 2001 at 16:42:10:
In Reply to: Re: I'm Driving Myself Crazy... posted by Denis Borris on December 02, 2001 at 14:44:10:
: : y^4-8y/y^2-4y-5 (Multiplied by) y-5/y^2+2y+1
: : (Divided by) y^3-y^2-2y/y^2+2y+1
: Change the final division to a multiplication (invert) and show CLEARLY! :
: [(y^4-8y)/(y^2-4y-5)] [(y-5)/(y^2+2y+1)] [(y^2+2y+1)/(y^3-y^2-2y)]
: factor 2nd term:
: [(y^4-8y)/(y+1)(y-5)] [(y-5)/(y^2+2y+1)] [(y^2+2y+1)/(y^3-y^2-2y)]
: cancel the cancellable terms:
: (y^4-8y)/(y^3-y^2-2y)
: divide by y:
: (y^3-8) / (y^2 - y - 2)
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=(y-2)*(y^2 + 2y + 4)/[(y -2)(y+1)]
=(y^2 + 2y + 4)/(y+1)
Still not 1
I wonder what did the teacher really mean by ".....you have a literal term in a Algebra problem the answer could never be one (as a number). " Did s/he mean to say thet (y + 1)/(y + 1) is not equal to 1????!!!!
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: well, as you can see, I don't get 1 as answer; but close...
: I must have goofed somewhere: find my goof and you got it!!