Posted by Denis Borris on December 02, 2001 at 14:44:10:
In Reply to: I'm Driving Myself Crazy... posted by SupperSync on December 02, 2001 at 14:14:44:
: y^4-8y/y^2-4y-5 (Multiplied by) y-5/y^2+2y+1
: (Divided by) y^3-y^2-2y/y^2+2y+1
Change the final division to a multiplication (invert) and show CLEARLY! :
[(y^4-8y)/(y^2-4y-5)] [(y-5)/(y^2+2y+1)] [(y^2+2y+1)/(y^3-y^2-2y)]
factor 2nd term:
[(y^4-8y)/(y+1)(y-5)] [(y-5)/(y^2+2y+1)] [(y^2+2y+1)/(y^3-y^2-2y)]
cancel the cancellable terms:
(y^4-8y)/(y^3-y^2-2y)
divide by y:
(y^3-8) / (y^3 - 3y - 2)
well, as you can see, I don't get 1 as answer; but close...
I must have goofed somewhere: find my goof and you got it!!