Posted by T.Gracken on November 12, 2002 at 21:09:05:
In Reply to: need help with coordiante geometry posted by Ryan on November 12, 2002 at 20:56:35:
: what is the eaquation of the line that passes through (5,5) and is parralel to the line 3x+4y=-16
recall that lines that are parallel have the same slope. so start by determining the slope of the line 3x+4y=-16.
there are many ways to do this. the way I like is to solve for y and look at the coefficient of x.
that is, if 3x+4y=-16
gives y = (-3/4)x - 4
so slope is -3/4
now that we know the slope, we can use the 'point-slpoe' formula and we get
y - 5 = (-3/4)(x - 5)
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