Re: solving a 3 variable system


[ Follow Ups ] [ Post Followup ] [ Main Message Board ] [ FAQ ]

Posted by T.Gracken on November 06, 2002 at 19:16:16:

In Reply to: solving a 3 variable system posted by Sarah on November 06, 2002 at 18:54:35:

: Can someone please explain in simple term how to solve a 3 variable system
: ex.
: 2x+y+z=8
: x+2y-z=-5
: z=2x+y

: Please help!!!!!!

it is amazing that everyone wants a "simple expanation". it doesn't always happen... deal with it!

but, for your problem... since you know z = 2x+y (last equation), substitue 2x+y for z in the first two equations and you have

2x + y + (2x+y) = 8
and
x + 2y - (2x+y) = -5

is that simple enough to start?

if not (i quit...). if so then simplify the two equations to get

4x + 2y = 8 ..(which is the same as 2x + y = 4)

and

-x + y = -5

Now solve this (2x2 system)

do it!!!


Follow Ups:



Post a Followup

Name:
E-Mail:

Subject:

Comments:

Optional Link URL:
Link Title:
Optional Image URL:


[ Follow Ups ] [ Post Followup ] [ Main Message Board ] [ FAQ ]