Posted by Denis Borris on November 05, 2002 at 00:10:34:
In Reply to: Different problem posted by Mike on November 04, 2002 at 22:23:21:
: A car and a bus set out at 3pm from the same point headed in the same
: direction. The average speed of the car is twice the average speed of the bus.
: In 2h the car is 68 mi ahead of the bus. Find the rate of the car.
Let bus speed = b; then car speed = 2b
bus: b = d/2 ; d = 2b
car: 2b = (d+68)/2 ; d = 4b - 68
So: 4b - 68 = 2b
2b = 68
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