Posted by Brad Paul on November 04, 2002 at 15:00:43:
In Reply to: Graphing of a Linear Equation posted by brook on November 04, 2002 at 11:51:14:
: I tried to graph this but can't get a perpendicular line.
: In the xy-plane, the graph of which of the following linear equations is perpendicular to the graph of the linear equation 3x-4y=0?
: The answer is: y=-4/3x+12.
The lines:
y=m x +b2
and
y=-(1/m)x+b2
Are perpendicular.