Re: Graphing of a Linear Equation


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Posted by Brad Paul on November 04, 2002 at 15:00:43:

In Reply to: Graphing of a Linear Equation posted by brook on November 04, 2002 at 11:51:14:

: I tried to graph this but can't get a perpendicular line.

: In the xy-plane, the graph of which of the following linear equations is perpendicular to the graph of the linear equation 3x-4y=0?
: The answer is: y=-4/3x+12.

The lines:

y=m x +b2

and

y=-(1/m)x+b2

Are perpendicular.


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