# Re: Sorry, last part is bad, fixed it.

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Posted by Joel on November 04, 2002 at 11:35:49:

In Reply to: Sorry, last part is bad, fixed it. posted by Jmiah on November 04, 2002 at 11:26:34:

: : Okay, here's the deal. I was doing a multiple choice test when I came across this one:

: : sqrt of (-16/7)=

: : A) 4/7 B) -4/7

: : C) 4(sqrt of 7)/7 (i) D) 4/(7i)

: : This is what i figured:

: : (sqrt of -16)/(sqrt of 7)=

: : 4i/sqrt of 7=

: : 4i(sqrt of 7)/7

: : The closet answer they have is C, which is also what they had listed in the book. I need to know how they got what they did. I don't have any clue how they seperated the i from the rest of the equation. Also, i IS sqrt of -1, or an imainary number.

: : THANX‼‼‼‼‼
: :
: : P.S. C) is 4 times sqrt of 7, over 7, times 5

(a*c)/b = (a/b)*c = a*(c/b) no matter what a, b and c are you can always rearrange the terms, as long as (in my example) a and c are always in the numerator and b is always the denominator.

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