Posted by Joel on November 01, 2002 at 19:05:03:
In Reply to: Re: i dun get it...me dun think yer #2 is correct... posted by Denis Borris on November 01, 2002 at 18:29:57:
: : : 2). in right triangle, BCD, BD=12, the measure of angle C=90 and the measure of angle DBC=47. Find BC to the nearest tenth. i got 8.8
: : Draw the triangle. BD=12 is the hypotenuse. BC is the side adjacent to
: : angle B (the 47-degree angle). So cos B = BC/BD or:
: : BC = 12 cos 47
: : BC = 8.7762
: BC = 8.184, ain't it? (BC is across angle D=43 degrees, so has to be < DC)
Of course. 12 cos 47 is 8.1840, and that's exactly what's written on my diagram. Then, for some reason I figured out the other side to see if it would all make sense. Then, I typed the wrong one.
I know ... no excuses, bla bla bla ...
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