Posted by Denis Borris on November 01, 2002 at 18:29:57:
In Reply to: Re: i dun get it... posted by Joel on November 01, 2002 at 18:15:39:
: : 2). in right triangle, BCD, BD=12, the measure of angle C=90 and the measure of angle DBC=47. Find BC to the nearest tenth. i got 8.8
: Draw the triangle. BD=12 is the hypotenuse. BC is the side adjacent to
: angle B (the 47-degree angle). So cos B = BC/BD or:
: BC = 12 cos 47
: BC = 8.7762
BC = 8.184, ain't it? (BC is across angle D=43 degrees, so has to be < DC)