Posted by Brad Paul on November 01, 2002 at 12:48:44:
In Reply to: factor this posted by jack on November 01, 2002 at 11:00:47:
: X^2-X+6
: What are the factors? I had this on a quiz today and totally blanked out.
T.Gracken is of cores correct for integers but if you have worked with
complex numbers I would consider the following the correct factorization:
x2-x+6=(x-(1+i sqrt(23))/2)(x-(1-i sqrt(23))/2)
I found the two values by solving:
x2-x+6=0 then rewrote as:
(x-x1)(x-x2)