Posted by T.Gracken on October 31, 2002 at 18:08:29:
In Reply to: derivative calculation posted by Stacy on October 31, 2002 at 17:35:48:
: 1st derivative of 3x^5 = 15x^4, or FORMULA ab^c = (a*c)b^(c-1).
: I understand that.
: 1st derivative of (x+3) / (x^2+2x) = -(3+x)(2+2x) / (2x+x^2)^2 + 1 / (2x+x^2)
: = -(6+6x+x^2) / x^2(2+x)^2
: Why is that?
: How is the FORMULA applied?