well....why make a small goof; might as well make it big!

Posted by Denis Borris on October 27, 2002 at 19:36:55:

In Reply to: Huh?... posted by Joel on October 27, 2002 at 18:18:17:

: : : solve
: : : 4x^(7/2)-8=0
: : : solve by substitution
: : : x^(2/3)+2x^(1/3)-8=0
: : : answers a){-4,2} b){-64,8} c){-8,64} d){-2,4}

: : methinks this thingie should be:

: : Solve by substitution:
: : 4x^(7/2)-8=0
: : x^(2/3)+2x^(1/3)-8=0

:
: : I'm saying that cause x=8 in 1st equation; which fits the 2nd equation.....
: ?????

: I don't know what it was at 2:53 AM but
: 4*8^(7/2) - 8 = 5784.61875148 this evening. :)
:

: : CHECK it, will ya!
: : If I'm correct, the go stand in the corner for 5 minutes...