Huh?...


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Posted by Joel on October 27, 2002 at 18:18:17:

In Reply to: Oh William me boy... posted by Denis Borris on October 27, 2002 at 02:53:29:

: : solve
: : 4x^(7/2)-8=0
: : solve by substitution
: : x^(2/3)+2x^(1/3)-8=0
: : answers a){-4,2} b){-64,8} c){-8,64} d){-2,4}

: methinks this thingie should be:

: Solve by substitution:
: 4x^(7/2)-8=0
: x^(2/3)+2x^(1/3)-8=0


: I'm saying that cause x=8 in 1st equation; which fits the 2nd equation.....
?????

I don't know what it was at 2:53 AM but
4*8^(7/2) - 8 = 5784.61875148 this evening. :)

: CHECK it, will ya!
: If I'm correct, the go stand in the corner for 5 minutes...




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