right triangles

Posted by Jerry on October 27, 2002 at 13:12:52:

Find all possible values of k so that (3,5), (5,-1), and (k,8)
are the vertices of a right triangle.

I start off getting an hypotenuse = 2sqrt(10) with sides 2 and 6, using (3,5) and (5,-1).
Looking for an easier way.
Thanks.

Follow Ups:

• Re: right triangles Joel 18:31:33 10/27/02 (1)
  • anutter way... Denis Borris 20:06:00 10/27/02 (0)

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