what's the formula for calculating the pulling of his leg vs. pulling my finger?

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Posted by MathBard on October 27, 2002 at 03:57:43:

In Reply to: NO diff: was just pulling Mr K's leg! posted by Denis Borris on October 27, 2002 at 03:50:45:

also:
Ich verstehe ein bisschen Franzozish, aber Ich muss "bitte schoen" sagen!
voila <<< pardon my French!

: : Mathematically they seem the same to me except that Soroban divided from 2 sec to per/sec BEFORE he sat up the problem. I worked both and got the same answer, so i assume they are each correct.
: : Here's my question: Is there a notation thingy that requires one to use the upper case R and the lower case r for the two unknowns, or can you make up your own like MR K. did? Is THAT what you are correcting?

: : the humbly Curious
: : MB

: :
: : : : : I am struggling with Algebra and my brain just can't handle word problems. Help is appreciated.

: : : : : With the wind, a quarterback passes a football 140 feet in 2 seconds. Against the wind, the same pass would have traveled 80 feet in 2 seconds. Find the rate of the pass and the rate of the wind.

: : : : : I'm thinking... (since d=r.t)

: : : : : 140=R.2
: : : : : 80=R.2

: : : : : If so, why can't I come up with a logical answer?
: : : : *******************************************
: : : : 1) What do you want to find (unknowns)? 2 unknowns:

: : : : the rate of the pass = P......and
: : : : the rate of the wind = W

: : : : 2) What are given: distance and time (Your choice of equation is correct)

: : : : 3) With the wind: Rate= P + W

: : : : 140 = (P +W)*2

: : : : 4) Against the wind: Rate = P - W

: : : : 80 = (P-W)*2

: : : : 5) In (3) and (4) you have two equations and two unknowns - solve it....

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