Posted by Denis Borris on October 27, 2002 at 02:53:29:
In Reply to: more help please ok i got alot more stuff posted by billy on October 26, 2002 at 22:57:32:
: solve
: 4x^(7/2)-8=0
: solve by substitution
: x^(2/3)+2x^(1/3)-8=0
: answers a){-4,2} b){-64,8} c){-8,64} d){-2,4}
methinks this thingie should be:
Solve by substitution:
4x^(7/2)-8=0
x^(2/3)+2x^(1/3)-8=0
I'm saying that cause x=8 in 1st equation; which fits the 2nd equation.....
CHECK it, will ya!
If I'm correct, the go stand in the corner for 5 minutes...