Posted by Subhotosh Khan on October 26, 2002 at 17:42:39:
In Reply to: I seem to be consistently just a few minutes slower :) -nt posted by Joel on October 26, 2002 at 17:34:01:
: : : Need help getting started
: : : I need to find the exact derivative of (sinx^2)(cosx^3). Do I apply the chain rule or the product rule first??
: : : Thanks
: : ******************************************
: : In this problem, youldalmost have to apply product rule first.
: : u = sinx^2 ...is this (sin (x^2) Or [sin(x)]^2
: : v = cosx^3...is this (cos (x^3) Or [cos(x)]^3
: : any way,
: : f = u * v
: : f' = u'*v + u*v'
: : While calculating u' and v' you would need to apply chain rule.