Posted by T.Gracken on October 26, 2002 at 07:54:19:
In Reply to: Re: you are attempting to look at a specific case... this is general case posted by Joel on October 25, 2002 at 22:37:50:
if we consider the polynomial with a=-1/3 and b=25/3 then we have
(-1/3)x3 - x2 - x + (25/3)
1. divide by (x-1) and the result is
(-1/3)x2 - (4/3)x - (7/3) + 6/(x-1) ...[i.e. remainder of 6]
2. divide by (x+2) and the result is
(-1/3)x2 - (1/3)x - (1/3) + 9/(x-1) ...[i.e. remainder of 9]