# Re: Inverse Circular Functions... yet again

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Posted by Jack on October 19, 2002 at 18:24:19:

In Reply to: Inverse Circular Functions... yet again posted by Liz on October 19, 2002 at 17:28:58:

: How am i to go about solving these:
: Sec-1 1.233
: Arccsc 2.647

: just please explain to me how i'm supposed to input the inverses of the secant and the cosecant functions into my calculator

: I'm sorry I'm not getting this but the text book doesn't help with anything and my teacher's too busy calling us all stupid to explain what she's doing (superiority complex .. she's disappointed that we're all girls at an all girls school)

: Thanks a bunch :D
: ~Liz

:arcsec 1.233 may be read as "What is the angle whose sec is 1.233?" You can solve this by using a trig function tables. Or if you have a calulator use it to find arccos(1/1.233) getting .625 radians or 35.803 degrees

:arccsc 2.647 = arcsin(1/2.647) = 22.2 degrees or .387 radians

• THANKS! Liz 16:06:57 10/20/02 (0)

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