Posted by Liz on October 18, 2002 at 18:11:17:
I have a quick question about how one would go about graphing arccot(x) in radians using a TI-83 Plus graphing calculator.
Now, what exactly is it that I have to input into my Y1 that would make the graph have a range of 0 [=] y [=] [pi], cross the y-axis at [pi]/2, and have a domain of infinity. I've tried 1/arctan(x), 1/(cos(x)/sin(x)), 1/(arccos(x)/arcsin(x)), and several other combinations that did not produce the desired graph. WHAT AM I DOING WRONG!?
Thanks a bunch :)
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