Re: problem


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Posted by Jonathan Burros on October 16, 2002 at 14:44:13:

In Reply to: problem posted by Joan on October 12, 2002 at 02:05:10:

: 7^(x-1)=(sqrt7)^(-2x^2)
: 7^(x-1)=7^[(1+(1/2))(-2x^2)]
: 7^(x-1)=7^[(3)x^2]

: (x-1)=[(3)x^2]

: I am not even close to the answer, now I am lost :(

7^(x-1)=(sqrt7)^(-2x^2)

The right side can be written

(7^(1/2))^(-2x^2)

= 7^(-x^2)

The origonal equation becomes

7^(x-1)= 7^(-x^2)

Equate the exponents on both sides

x-1 = -x^2

x^2 + x - 1 = 0

Solve this by the quadratic formula

x = [-1 +-sqrt[1^2 - 4(1)(-1)]]/[2(1)]

= (-1 +- sqrt 5)/2



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