Posted by Desire on October 14, 2002 at 18:34:08:
In Reply to: Look at #20 again posted by Joel on October 14, 2002 at 15:26:52:
x=2y
x-(y/4)=21
[(2y)-(y/4)=21](4)
(8y)-(y)=21(4)
(7y)=84
y= 84/7
y = 12
so 2y = x= 24
an 12/4 = 3
so 24-3=21
aha :)
Thanx again Joel
: : : 20) one number is twice another #. If u take one-fourth of the lesser # and subtract it from the greater # u get 21 find the leser # and the greater #??
: : x = 2y if x = 2y which one is the lesser, x or y?
: "take one-fourth of the lesser and subtract it from the greater"
: : (x/4)-2y=21 is that what you're doing here?
: : (2y/4)-2y = 21
: : (2y)-8y=84
: : 6y=64
: : y = 8
: : so the lesser would be 4 since 4 = (8/2) and the greater would be 8.