Posted by Joel on October 13, 2002 at 19:17:16:
In Reply to: question posted by Lisa on October 13, 2002 at 18:06:12:
: I posted this below but I think what I was asking was misunderstood. The question was to find the ration and I was asking if I had written the ratio correctly.
: The noise level of one sound is 20 decibals higher than that of a second sound. Find the ratio of the intensity of the first sound to the second sound.
: L = 10 (log I_1/I_2)= 10 log 100 = 20
The ratio is (louder divided by softer), so I guess it depends on how you define your I_1 and I_2. I think it's usually written as I1/I0 where I1 is the sound in question and I0 is the "reference level" -- that is, what the sound in question is being compared to.
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