log problem

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Posted by Lisa on October 12, 2002 at 16:29:31:

The noise level of one sound is 20 decibals higher than that of a second sound. Find the ratio of the intensity of the first sound to the second sound.

Is this the way to do a problem like this.
L = 10 (log I_1/I_2)= 10 log 100 = 20

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