I see what they did they used the quadratic equation


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Posted by Joan on October 12, 2002 at 15:47:16:

In Reply to: Re: problem posted by Joan on October 12, 2002 at 15:34:34:

: Thanx for your help Mr. k. :)
: so I worked out the problem
: ===> x = (-1.6180340) and x = (.6180340)
: The book had this in radical form, so I wonder if there was a different way of doing this problem or if they just converted these decimals to radical form. I don't know how to get the radical form from these decimals :(, could someone show me how please.
: x= -(1/2)+(1/2)sqrt 5
: x= -(1/2)-(1/2)sqrt 5


: : : 7^(x-1)=(sqrt7)^(-2x^2)

: : : 7^(x-1)=7^[(1+(1/2))(-2x^2)]...this should be ..7^(x-1)=7^[(1/2)*(-2x^2)]

: : : 7^(x-1)=7^[(3)x^2]...this should be ..7^(x-1)=7^[-x^2]

: : : (x-1)=[-x^2]

: : x^2 + x - 1 = 0 ..........take it from here Quadratic equation

: : : I am not even close to the answer, now I am lost :(




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