Posted by Bob on October 11, 2002 at 22:01:38:
In Reply to: Re: Area problem posted by Soroban on October 11, 2002 at 17:31:56:
: Consider triangle DFC. Its base is 15b/16.
: By similar triangles, its altitude is h/16.
: Hence, the area of EFC = (1/2)(15b/16)(h/16) = (15/256)(bh/2).
Is DFC a typo?
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