Re: quad problem....bye, Lisa...


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Posted by Denis Borris on October 11, 2002 at 00:18:53:

In Reply to: quad problem posted by Lisa on October 10, 2002 at 21:37:36:

: e^(2t)-3e^+2=0
: let x =e^t
: so x^2-3x+2=0
: (x-2)(x-1)
: (e^t-2)(e^t-1)
: so ln^e = ln2
: and ln^e = 1
: and that is wrong, the answer is suppose to be 0 and ln2
: What did I do wrong?




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