Posted by Lisa on October 10, 2002 at 21:37:36:
e^(2t)-3e^+2=0let x =e^tso x^2-3x+2=0(x-2)(x-1)(e^t-2)(e^t-1)so ln^e = ln2and ln^e = 1and that is wrong, the answer is suppose to be 0 and ln2What did I do wrong?
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Comments: : e^(2t)-3e^+2=0 : let x =e^t : so x^2-3x+2=0 : (x-2)(x-1) : (e^t-2)(e^t-1) : so ln^e = ln2 : and ln^e = 1 : and that is wrong, the answer is suppose to be 0 and ln2 : What did I do wrong?
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