# Re: Algebra 2

[ Follow Ups ] [ Post Followup ] [ Main Message Board ] [ FAQ ]

Posted by MathBard on October 09, 2002 at 19:39:33:

In Reply to: Algebra 2 posted by Stacy on October 09, 2002 at 16:55:52:

: Can you explain and show me how to do these problems?
: 1. Find three consecutive odd intergers such that 7 times the sum of the first and the third is 120 less than 10 times the opposite of the second?

: 2. Find three consecutive even intergers such that 6 times the sum of the first and the third is 8 less than 14 times the second?

: WE are desperately seeking help. We are homeschooler and I, the mom, have been out of school for a long time! We would appreciate any help you can give us.
: Thanks

The "trick" to these is to find ONE variable to use, and do all your math to it. The "consecutive even OR odd integer" thingy just tells you that the gap between each integer is +2. USE THAT!
let x equal your first even integer.
That means your second would have to be x+2 and your third X+4.
Now, fit them into what your problem tells you to do to them. Do it piece by piece.
The sum of the first and third is ...
x+x+4
six times that
6(x+x+4)
...8 less than... if you +8 it will equal...
6(x+x+4)+8=
14 times the second
14(x+2)
so...
6(x+x+4)+8=14(x+2)
now you have a problem you can work....

MathBard
PS sorry about all the typos in my other message i sent before i proofed it!

Name:
E-Mail:

Subject: