Re: Here's another one


[ Follow Ups ] [ Post Followup ] [ Main Message Board ] [ FAQ ]

Posted by Subhotosh Khan on October 09, 2002 at 10:07:49:

In Reply to: Here's another one posted by Jmiah on October 08, 2002 at 20:47:03:

: Here's another one. Please remember that the people who wrote the book are only human.

: 36[x^5][y^2][z^-2]/9[x^0][y^4][z^-3]=

: I got:
: 4[x^5][y^-2][z^-5]

: The book said:
: 4[x^5][y^-2][z]

: Please remember th double negative. Thanx!
*************************
The problem should be written:

36[x^5][y^2][z^-2]/{9[x^0][y^4][z^-3]}

=36/9 *x^(5-0) * y^(2-4) * z^(-2-(-3))

=4 x^5 * y^(-2)* z^(-2+3) ....[without forgetting the double negetive]

So book is CORRECT

by the way, "problem as presented" will have following answer:

36 * [x^5] * [y^2] * [z^(-2)]/9 * [x^0] * [y^4] * [z^-3]

=4 * [x^5] * [y^6] * [z^(-5)]




Follow Ups:



Post a Followup

Name:
E-Mail:

Subject:

Comments:

Optional Link URL:
Link Title:
Optional Image URL:


[ Follow Ups ] [ Post Followup ] [ Main Message Board ] [ FAQ ]