Posted by Denis Borris on October 08, 2002 at 22:36:14:
In Reply to: Here's another one posted by Jmiah on October 08, 2002 at 20:47:03:
: Here's another one. Please remember that the people who wrote the book are only human.
: 36[x^5][y^2][z^-2]/9[x^0][y^4][z^-3]=
: I got:
: 4[x^5][y^-2][z^-5]
: The book said:
: 4[x^5][y^-2][z]
: Please remember th double negative. Thanx!
remember that a^0 = 1 and a^-b = 1/a^b; so:
{36[x^5][y^2][z^-2]} / {9[x^0][y^4][z^-3]}=
{36[x^5][y^2] / [z^2]} / {9[y^4] / [z^3]}=
{36[x^5][y^2] / [z^2]} * {[z^3] / 9[y^4]}=
{36[x^5][y^2][z^3]} / {[z^2]9[y^4]}=
4[x^5][y^-2][z]
Note: [y^-2] is arrived at this way: y^2/y^4 = y^2*y^-4 = y^-2
Are you ok with that, Jeremiah ?