Answers to other questions

Posted by Subhotosh Khan on October 08, 2002 at 12:09:22:

In Reply to: other questions posted by Kurt on October 08, 2002 at 11:47:36:

: I understand what needs to be done, Mr K, but can't finish it.
: Too many things I haven't seen before.

: :mAOB = T
: I understand "AOB", but what is T? degrees, like 75 degrees? Yes
: What does "m" mean? It is short of "measure of" or "value of" angle AOB

: :From that you can get the area of the base(A_1)
: Why do I need to get the area? Look below

: :volume of small cone (V_1)=1/3*R*A
: where does that come from? V = (pi r^2 h) / 3, is it not? In this case A = pi * r^2 .... and h = R (the radius of the circle you started with) so we are talking about the same thing
***********************************
Assume mAOB = T (in radians)

So chord AB = R * T (definition of angle)

So the circumference of the base of the small cone

2* pi * r = R * T ? (r = radius of the circular base of the small cone)

r = R * T/(2*pi)

V_1 = (pi)* r^2 * h / 3

= (pi)* [R * T/(2*pi)]^2 * R / 3

= R^3/(12*pi) * T^2

Similarly find V_2

Follow Ups:

• stepping in... Denis Borris 22:48:24 10/08/02 (7)
  • Mr B... you lost me ...I'll do the full problem below Subhotosh Khan 10:22:54 10/09/02 (6)
    • I got "unlost" .. Mr B you are partially correct Subhotosh Khan 11:21:17 10/09/02 (5)
      • Mr B you are partially correct : I think I'm FULLY correct.... Denis Borris 12:53:27 10/09/02 (4)
        • Hokay.... Denis Borris 16:26:44 10/09/02 (3)
          • Please check your equation... Subhotosh Khan 16:53:07 10/09/02 (2)
            • NO! Denis Borris 18:14:54 10/09/02 (1)
              • Yes .... Subhotosh Khan 08:54:59 10/10/02 (0)

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