Posted by Denis Borris on October 03, 2002 at 16:58:40:
In Reply to: factoring problem posted by lisa on October 03, 2002 at 15:59:00:
: I am not sure what the easiest fastest way to do a problem like this. Do I expand first, it really gets messy when I do that.
quickly; have you tried:
let x-3=a; then 2x-3=a+x; so:
a^2(a+x)^4 + 12a^3(a+x)^2
may be easier to "handle"; substitute back in at end....
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