# Re: O.K. here's the way I recommend

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Posted by Jmiah on October 03, 2002 at 11:35:09:

In Reply to: O.K. here's the way I recommend posted by T.Gracken on October 03, 2002 at 10:38:08:

: : This is the deal. Me and the answer key don't agree, and so my mom wants me to figure it out another way, to make sure which is right. Now, remember the double negative.
:
: When solving equations where all the variables (letters) are raised to the first power I proceed as follows:

: first: simplify if possible (that is, add like terms where it's allowed)

: then:
: 1. eliminate any parenthesis using the distributive property
: 2. eliminate fractions by multiplying each term by the LCD
: 3. isolate variable terms (that is, get all terms with a letter on one side of the equal and all terms without a letter on the other side)
: 4. divide both sides by whatever is multiplied to the letter.

: So...
: : (11-4)^2 / 7-(3-9)=14(r-2r)

: first:
: 72/7 - (-6) = 14(r-2r) which can be further reduced to

: 13 = -14r

: which is exactly what you have.

: since steps 1 thru 3 are not needed, just divide by -14 and you get your result.

: r = -13/14.

: so unless you copied or wrote the problem incorrectly, your answer is the correct one.

: good job!

:
: : [that's not a 2/7 exponent, its squared, divided by 7]

: : (7^2)/7-(3-9)=-14r

: : 49/7-(-6)=-14r

: : 7-(-6)=-14r

: : 13=-14r

: : -13/14=r

: : They got -1/14, becuase they forgot the double negative. I'm just making sure I remember double negatives well enough.

Thanks. I'm homeschooled, so and since my mom's not a math teacher, she wants me to double check all this stuff. Thanks again.

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